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-rw-r--r--vendor/github.com/mattermost/rsc/regexp/regmerge/sort.go199
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diff --git a/vendor/github.com/mattermost/rsc/regexp/regmerge/sort.go b/vendor/github.com/mattermost/rsc/regexp/regmerge/sort.go
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+// Copyright 2012 The Go Authors. All rights reserved.
+// Use of this source code is governed by a BSD-style
+// license that can be found in the LICENSE file.
+
+// Copy of go/src/pkg/sort/sort.go, specialized for []int
+// and to remove some array indexing.
+
+package main
+
+func min(a, b int) int {
+ if a < b {
+ return a
+ }
+ return b
+}
+
+// Insertion sort
+func insertionSort(data []int, a, b int) {
+ for i := a + 1; i < b; i++ {
+ for j := i; j > a && data[j] < data[j-1]; j-- {
+ data[j], data[j-1] = data[j-1], data[j]
+ }
+ }
+}
+
+// siftDown implements the heap property on data[lo, hi).
+// first is an offset into the array where the root of the heap lies.
+func siftDown(data []int, lo, hi, first int) {
+ root := lo
+ for {
+ child := 2*root + 1
+ if child >= hi {
+ break
+ }
+ if child+1 < hi && data[first+child] < data[first+child+1] {
+ child++
+ }
+ if !(data[first+root] < data[first+child]) {
+ return
+ }
+ data[first+root], data[first+child] = data[first+child], data[first+root]
+ root = child
+ }
+}
+
+func heapSort(data []int, a, b int) {
+ first := a
+ lo := 0
+ hi := b - a
+
+ // Build heap with greatest element at top.
+ for i := (hi - 1) / 2; i >= 0; i-- {
+ siftDown(data, i, hi, first)
+ }
+
+ // Pop elements, largest first, into end of data.
+ for i := hi - 1; i >= 0; i-- {
+ data[first], data[first+i] = data[first+i], data[first]
+ siftDown(data, lo, i, first)
+ }
+}
+
+// Quicksort, following Bentley and McIlroy,
+// ``Engineering a Sort Function,'' SP&E November 1993.
+
+// medianOfThree moves the median of the three values data[a], data[b], data[c] into data[a].
+func medianOfThree(data []int, a, b, c int) {
+ m0 := b
+ m1 := a
+ m2 := c
+ // bubble sort on 3 elements
+ if data[m1] < data[m0] {
+ data[m1], data[m0] = data[m0], data[m1]
+ }
+ if data[m2] < data[m1] {
+ data[m2], data[m1] = data[m1], data[m2]
+ }
+ if data[m1] < data[m0] {
+ data[m1], data[m0] = data[m0], data[m1]
+ }
+ // now data[m0] <= data[m1] <= data[m2]
+}
+
+func swapRange(data []int, a, b, n int) {
+ for i := 0; i < n; i++ {
+ data[a+i], data[b+i] = data[b+i], data[a+i]
+ }
+}
+
+func doPivot(data []int, lo, hi int) (midlo, midhi int) {
+ m := lo + (hi-lo)/2 // Written like this to avoid integer overflow.
+ if hi-lo > 40 {
+ // Tukey's ``Ninther,'' median of three medians of three.
+ s := (hi - lo) / 8
+ medianOfThree(data, lo, lo+s, lo+2*s)
+ medianOfThree(data, m, m-s, m+s)
+ medianOfThree(data, hi-1, hi-1-s, hi-1-2*s)
+ }
+ medianOfThree(data, lo, m, hi-1)
+
+ // Invariants are:
+ // data[lo] = pivot (set up by ChoosePivot)
+ // data[lo <= i < a] = pivot
+ // data[a <= i < b] < pivot
+ // data[b <= i < c] is unexamined
+ // data[c <= i < d] > pivot
+ // data[d <= i < hi] = pivot
+ //
+ // Once b meets c, can swap the "= pivot" sections
+ // into the middle of the slice.
+ pivot := lo
+ a, b, c, d := lo+1, lo+1, hi, hi
+ dpivot := data[pivot]
+ db, dc1 := data[b], data[c-1]
+ for b < c {
+ if db < dpivot { // data[b] < pivot
+ b++
+ if b < c {
+ db = data[b]
+ }
+ continue
+ }
+ if !(dpivot < db) { // data[b] = pivot
+ data[a], data[b] = db, data[a]
+ a++
+ b++
+ if b < c {
+ db = data[b]
+ }
+ continue
+ }
+ if dpivot < dc1 { // data[c-1] > pivot
+ c--
+ if c > 0 {
+ dc1 = data[c-1]
+ }
+ continue
+ }
+ if !(dc1 < dpivot) { // data[c-1] = pivot
+ data[c-1], data[d-1] = data[d-1], dc1
+ c--
+ d--
+ if c > 0 {
+ dc1 = data[c-1]
+ }
+ continue
+ }
+ // data[b] > pivot; data[c-1] < pivot
+ data[b], data[c-1] = dc1, db
+ b++
+ c--
+ if b < c {
+ db = data[b]
+ dc1 = data[c-1]
+ }
+ }
+
+ n := min(b-a, a-lo)
+ swapRange(data, lo, b-n, n)
+
+ n = min(hi-d, d-c)
+ swapRange(data, c, hi-n, n)
+
+ return lo + b - a, hi - (d - c)
+}
+
+func quickSort(data []int, a, b, maxDepth int) {
+ for b-a > 7 {
+ if maxDepth == 0 {
+ heapSort(data, a, b)
+ return
+ }
+ maxDepth--
+ mlo, mhi := doPivot(data, a, b)
+ // Avoiding recursion on the larger subproblem guarantees
+ // a stack depth of at most lg(b-a).
+ if mlo-a < b-mhi {
+ quickSort(data, a, mlo, maxDepth)
+ a = mhi // i.e., quickSort(data, mhi, b)
+ } else {
+ quickSort(data, mhi, b, maxDepth)
+ b = mlo // i.e., quickSort(data, a, mlo)
+ }
+ }
+ if b-a > 1 {
+ insertionSort(data, a, b)
+ }
+}
+
+func sortInts(data []int) {
+ // Switch to heapsort if depth of 2*ceil(lg(n)) is reached.
+ n := len(data)
+ maxDepth := 0
+ for 1<<uint(maxDepth) < n {
+ maxDepth++
+ }
+ maxDepth *= 2
+ quickSort(data, 0, n, maxDepth)
+}